Nilai dari ∫(3x + 4)(x + 2)dx = 2−1…

Integral

∫(3x + 4)(x + 2) dx [2 -1]
= ∫(3x² + 10x + 8) dx
= 3/3 x³ + 10/2 x² + 8x
= x³ + 5x² + 8x
= (2³ – (-1)³) + 5(2² – (-1)²) + 8(2 – (-1))
= 9 + 5 × 3 + 8 × 3
= 9 + 15 + 24
= 48