Nilai integral (3x+1)(2x-5)dx adalah?

Nilai integral (3x+1)(2x-5)dx adalah?

Jawaban Terkonfirmasi

$int ( 3x+1 )(2x-5) dx = int 6x^2-13x-5 + C \ \ leftrightarrow = frac{6}{2+1} x^{2+1} - frac{13}{1+1}x^{1+1}- frac{5}{0+1}x^{0+1} + C \ \ leftrightarrow = 2x^2 - frac{13}{2} x^2 - 5x + C \ \ leftrightarrow = frac{1}{2} ( 4x^3 - 13x^2 - 10x ) + C$

Jawaban Terkonfirmasi

$intlimits {(3x + 1)(2x - 5)} , dx$ = $intlimits{ 6x^{2} - 13x - 5} , dx$
= $frac{6}{2 + 1}$ $x^{2 + 1}$ - $frac{13}{1 + 1}$ - $frac{5}{0 + 1}$ $x^{0 + 1}$ + C
= 2x³ - $frac{13}{2}$ x² – 5x + C
= $frac{1}{2}$ .(4x³ – 13x² – 10x) + C