Nilai limit x=0 ((2x/3)^3)/ (1-cos^2(2x/3).tan6x)

Jawaban:

lim (x->0) ( 2 tan 6x . sin 2x )/ ( 1 – cos x)

lim (x ->0) (2 tan 6x. sin 2x) / (2 sin² 1/2 x)

= 2(6)(2) / ( 2 (1/2)²

= 24 / (1/2)

= 48