Nilai minimum dari fungsi f(x) =x²-8x+12adalah

Nilai minimum dari f ( x ) = x² – 8x + 12

a = 1
b = -8

nilai x

x = -b / 2a
x = – (-8) / 2a
x = 8/2
x = 4

f ( 4 ) = x² – 8x + 12
f ( 4 ) = 4² – 8 × 4 + 12
f ( 4 ) = 16 – 32 + 12
f ( 4 ) = -4