Nilai mutlak 2x – 1 =nilai mutlak x + 3

|2x-1| = |x+3|
(2x-1)² = (x+3)²
4x² -4x +1 = x² +6x +9
4x² -4x +1 – x² – 6x -9 = 0
3x² -10x -8 = 0
(3x²-12x) (2x-8) = 0
3x (x-4) 2(x-4) = 0
(3x+2) (x-4) = 0
∴ 3x+2 = 0      atau   x-4 = 0
   3x = -2                   x = 4
   x = -2/3