Nilai n yg memenuhi persamaan n! ____________=10 (n-2)!x4!

By Admin ReiPosted on October 29, 2022

Nilai n yg memenuhi persamaan n!
____________=10
(n-2)!x4!

Jawaban :

n = 16

Penjelasan :

$frac{n!}{(n - 2)! : 4!} =10 \ frac{n : (n - 1) :(n - 2)!}{(n - 2)!} = 240 \ {n}^{2} - n = 240 \ {n}^{2} - n - 240 = 0 \ (n + 15) : (n - 16) \ n = 16$