Nilai stasioneri dari fungsi f(x)=3x²-12x+9 adalah​

aplikasi turunan

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f (x) = 3x² – 12x + 9

0 = f' (x) → stasioner

0 = 6x – 12

x = 2

subs. x = 2 kdlam f (x)

f (2) = 3.2²- 12.2 + 9

f (2) = 12 – 24 + 9

f (2) = -3