Nilai x/y dari sistem persamaan 6/x-10/y=2 dan y/4-x/5=xy/20 adalah
aljabar
6/x – 10/y = 2 dan y/4 – x/5 = xy/20
nilai x/y = ??
6/x – 10/y = 2
→ (6y – 10x)/(xy) = 2
→ 6y – 10x = 2xy
→ 3y – 5x = xy
y/4 – x/5 = xy/20
→ (5y – 4x)/(20) = xy/20
→ 5y – 4x = xy
xy = xy
→ 5y – 4x = 3y – 5x
→ 2y = -x
→ x = -2y
→ x/y = -2
semoga membantu