Nilai x yang memenuhi persamaan 2 sin (2x-60 )+ akar 3=0, 0<samadengan × <samadengan 360°

2 sin (2x-60) + √3 = 0
2 sin (2x-60) = -√3
sin (2x-60) = -1/2√3
sin (2x-60) = sin (180° + 60°)
sin (2x-60) = sin 240°
2x – 60 = 240 + k.360
2x = 300 + k.360
x = 150 + k.180
k = 0, x = 150
k = 1, x = 330
k = 2, x = 510
atau :
2x – 60 = (180-240) + k.360
2x – 60 = -60 + k 360
2x = 0 + k.360
x = 0 + k.180
k = 0, x = 0
k = 1, x = 180
k = 2, x = 360

interval 0<= x <= 360, berarti hp =
{0°,150°,180°,330°,360°}