No 1… (X²+2x-3) (x²+1) == No 2… (X+y-5) (x-y-5) =

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No 1… (X²+2x-3) (x²+1) ==
No 2… (X+y-5) (x-y-5) =

Penjelasan dengan langkah-langkah:

1. : ( {x}^{2} + 2x - 3)( {x}^{2} + 1) = \ : : : = {x}^{4} + {x}^{2} + {2x}^{3} + 2x - {3x}^{2} - 3 \ : : : = {x}^{4 } + {2x}^{3} + {x}^{2} - {3x}^{2} + 2x - 3 \ = {x}^{4} + {2x}^{3} - {2x}^{2} + 2x - 3 \ \ 2.(x + y - 5)(x - y - 5) = \ = {x}^{2} - xy - 5x + xy - {y}^{2} - 5y - 5x + 5y + 25 \ = {x}^{2} - {y}^{2} - xy + xy - 5x - 5x - 5y + 5y + 25 \ = {x}^{2} - {y}^{2} - 10x + 25

Jawaban:

1).

= (x² + 2x – 3)(x² + 1)

= x²(x² + 1) + 2x(x² + 1) – 3(x² + 1)

= x⁴ + x² + 2x³ + 2x – 3x² – 3

= x⁴ + x² – 3x² + 2x³ + 2x – 3

= x⁴ – 2x² + 2x³ + 2x – 3

atau

= x⁴ + 2x³ – 2x² + 2x – 3

2).

= (x + y – 5)(x – y – 5)

= x(x – y – 5) + y(x – y – 5) – 5(x – y – 5)

= x² – xy – 5x + xy – y² – 5y – 5x + 5y + 25

= x² – xy + xy – 5x – 5x – y² – 5y + 5y + 25

= x² – 0 – 10x – y² – 0 + 25

= x² – 10x – y² + 25