No 2 aja...ayo..yang baik..

No 2 aja…ayo..yang baik..

Jawaban:

Diketahui :

Q1 = 4μC = 4×10⁻⁶ C

Q2 = 8μC = 8×10⁻⁶ C

r = 60 cm = 6×10⁻¹ m

k = 9 x 10⁹

Ditanya : F ?

Jawab :

$f = k frac{q1 times q2}{r {}^{2} }$

$f = 9 times 10 {}^{9} frac{(4 times 10 {}^{ - 6} )(8 times 10 {}^{ - 6} )}{(6 times 10 {}^{ - 1}) {}^{2} }$

$f = frac{288 times 10 {}^{ - 3} }{36 times 10 {}^{ - 2} }$

$f = 8 times 10 {}^{ - 1}$

$f = 0.8 : newton$

Jawaban:

0,8 N

Penjelasan:

diketahui:

q1 = 4×10^-6 C

q2 = 8×10^-6 C

r = 60cm = 6,0 m

ditanyakan:

besar gaya yg terjadi antara dua buah muatan tersebut

penyelesaian:

F = k(q1.q2)/r²

F = 9×10^9 NM²/C²(4×10^-6C)(8×10^-6C)/(0,6m)²

F = 9×10^9 NM²/C²(32 x 10^-12 C²) / 0,36 m²

F = (9×32:0,36) x 10^(9-12) N

F = 800 x 10^-3 N

F = 800 x 1/10³ N

F = 800 x 1/1000 N

F = 0,8 N