No.4 gimana caranya ya?

Bab Limit
Matematika SMA Kelas XI

24] Lim t → 5 
(2t² – 5t – 25) / (125 – t³)
= ((2t + 5) (t – 5)) / ((5 – t) (5² + 5t + t²))
= (- (2t + 5) (5 – t)) /((5 – t) (25 + 5t + t²))
= (-2t – 5) / (t² + 5t + 25)
masukkan t →5
= (-2 . 5 – 5) / (5² + 5 . 5 + 25)
= -15 / 75
= – 1/5

jawabannya B