Nomor 3 dan 4 #pakaijalanya

Nomor 3 dan 4 #pakaijalanya

Jawaban Terkonfirmasi

no. 3 soal terpotong bagiab atas (tak terbaca)
no.4 )

x = $frac{d left[begin{array}{ccc}2&6\-5&-3\end{array}right] }{d left[begin{array}{ccc}2&6\1&-3\end{array}right] }$
= $frac{(2 - 3) - (6 . - 5)}{(2 . - 3) - (6 . 1)}$
= $frac{24}{- 12}$
= – 2
y = $frac{d left[begin{array}{ccc}2&2\1&- 5\end{array}right] }{d left[begin{array}{ccc}2&6\1&- 3\end{array}right] }$
= $frac{( 2 . - 5) - (2 . 1)}{(2 . - 3) - (6 . 1)}$
= $frac{- 12}{- 12}$
= 1
x² + 2xy + y² = (x + y)²
= (- 2 + 1)²
= (- 1)²
= 1