Besar luas permukaan bangun ruang di samping adalah…
A. 216
B. 234
C. 432
D. 423
P = 8cm L = 6cm. T = 12cm
Diketahui:
p = 8 cm
l = 6 cm
t = 12 cm
Ditanya:
Lp = … cm²
Jawaban:
Lp = 2 × ((p × l) + (p × t) + (l × t))
= 2 × ((8×6) + (8×12) + (6×12))
= 2 × (48 + (8×12) + (6×12))
= 2 × (48 + 96 + (6×12))
= 2 × (48 + 96 + 72)
= 2 × (144 + 72)
= 2 × 216
= 432 cm² Opsi C
2 x (p x l) (p x t ) ( L x t ))
2 x (8 x 6) +(8 x12) +(6 x 12)
2 x (48 + 96 + 72)
=432 cm2