Pada segitiga ABC diatas, besar Sudut AEF = sudut BCA.Tolong bantu jawab ya. Terimakasih ^^
Jawaban Terkonfirmasi
∠AEF=∠BCA, ∠A=∠A (dua sudut sama, tandanya sebangun)
AEF => ∠AEF, ∠A, ∠EFA
BCA => ∠BCA, ∠A, ∠ABC
AC/AE =BC/EF
EF = AE.BC/AC = 6.12/8 = 9 cm
AB/AF=BC/EF
AF=AB.EF/BC=10.9/12=15/2
CF = AC-AF = 8-15/2 = 1/2
A) ae/eb = 6/4 = 3/2
bc/ac = 12/8 = 3/2
jadi segitiga abc dengan segitiga aef
B) EF = ef/bc = ae/eb
= ef/12 = 6/4
= 4ef = 72
= ef = 72/4
= 18