Pakai cara subtitusi atau eliminasi
3x+5y=8
2x-3y=7
tolong dibantu
3x+5y=8
2x-3y=7
metode matriks
x = (-24-35) / (-9-10) = -59/-19 = 59/19
y = (21-16) / (-9-10) = 5/-19
metode eliminasi & substitusi (campuran)
3x+5y=8 |x2| 6x+10y=16
2x-3y=7 |x3| 6x-9y = 21
—————–(-)
19y = -5
y = -5/19
3x+5y=8
3x+5(-5/19) =8
3x-25/19=8
3x=8+25/19
3x = (152+25)/19
3x = 177/19
x= 177/19 : 3
x = 59/19
metode substitusi
biar gampang : 3x+5y=8
2x-3y=7
————-(-)
x + 8y =1
x = 1-8y
x=1-8y —->3x+5y=8
3(1-8y)+5y = 8
3-24y+5y=8
-19y = 8-3
-19y = 5
y = -5/19
x=1-8y
= 1-8(-5/19)
= 1+40/19
= 19/19 + 40/19
= 59/19
3x + 5y = 8 dikalikan 3 = 9x + 15y = 24
2x - 3y = 7 dikalikan 5 = 10x – 15 y = 35 +
-x = -11
x = 11
2x – 3y = 7
2(11) – 3y = 7
22 – 3y = 7
-3y = 7 – 22
-3y = -15
y = -15
-3
y = 5
x = 11 dan y = 5