Pakai cara ya kak terima kasih

Pakai cara ya kak terima kasih

Jawab:

$displaystylefrac{6}{2+sqrt6}=frac{6}{2+sqrt6}cdotfrac{2-sqrt6}{2-sqrt6}\frac{6}{2+sqrt6}=frac{6(2-sqrt6)}{2^2-(sqrt6)^2}\frac{6}{2+sqrt6}=frac{6(2-sqrt6)}{4-6}\frac{6}{2+sqrt6}=frac{6(2-sqrt6)}{-2}\frac{6}{2+sqrt6}=-3(2-sqrt6)\frac{6}{2+sqrt6}=3(sqrt6-2)$

$displaystylelogfrac{11}5+logfrac{14}3-logfrac{22}{15}=logfrac{displaystylefrac{11}5timesfrac{14}3}{displaystyle frac{22}{15}}\logfrac{11}5+logfrac{14}3-logfrac{22}{15}=logfrac{displaystylefrac{11}{15}times14}{displaystyle frac{11}{15}times2}\logfrac{11}5+logfrac{14}3-logfrac{22}{15}=logfrac{14}{2}\logfrac{11}5+logfrac{14}3-logfrac{22}{15}=log7$

Beberapa konsep yang dipakai:

$displaystyletriangleright~(a+b)(a-b)=a^2-b^2\triangleright~log_ab_1+log_ab_2+cdotslog_ab_n=log_a(b_1times b_2timescdotstimes b_n)\triangleright~log_ab-log_ac=log_afrac{b}{c}$