Pake cara yaaa……
Penyelesaian:
U6 = a + 5b = 35
U12 = a + 11b = 65
11b – 5b = 65 – 35
6b = 30
b = 5
a = 35 – 5b
a = 35 – 5(5)
a = 10
suku ke-50
U50 = a + 49b
U50 = 10 + 49 (5)
U50 = 255
Jumlah 50 suku pertama
Sn = n/2 (a + Un)
S50 = 50/2 (10 + 255)
S50 = 25 (265)
S50 = 6.625
====================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Barisan dan Deret
Kode: 11.2.7
Kata Kunci: barisan aritmatika