Panjang busur di depan sudut 20 derajat adalah 10,46 cm luas juring lingkaran nya adalah​

JAWABAN ;

r=20 cm

r=20 cma.Busur 30° = 30/360 x 2πr

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm =10,5 cm ( pembulatan)

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm =10,5 cm ( pembulatan)b.juring 45° =45/360 x πr²

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm =10,5 cm ( pembulatan)b.juring 45° =45/360 x πr² =1/8 x 3,14 x 20²

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm =10,5 cm ( pembulatan)b.juring 45° =45/360 x πr² =1/8 x 3,14 x 20² =1/8 x 3,14 x 400

r=20 cma.Busur 30° = 30/360 x 2πr =1/12 x 2 x 3,14 x 20 =10,4467 cm =10,5 cm ( pembulatan)b.juring 45° =45/360 x πr² =1/8 x 3,14 x 20² =1/8 x 3,14 x 400 =157 cm²