Para perkalian (2x +5)(3x + p) = 6×2 + 7x + q nilai p dan q berturut – turut adalah

(2x +5)(3x + p) = 6x² + 7x + q

2x.3x + 2x.p + 5.3x + 5p = 6x² + 7x + q

6x² + 2px + 15x + 5p = 6x² + 7x + q

→ 2p + 15 = 7
2p = 7 – 15
2p = -8
p = -8/2
p = -4

→ 5p = q
5(-4) = q
-20 = q

jadi nilai p = -4 dan q = -20

(2x+5)(3x+p)=6x^2+7x+q
6x^2+(2px+15x)+5p=6x^2+7x+q
a. 2px+15x=7x
2px=-8x
p = -4
b. 6x^2+7x+5.-4=6x^2+7x+q
-20 = q