Pd ssunan pgas A, B, C, & D, tntukan nilai prbandingan

a. Prtmbahan pnjang ssunan pegas:
(i) Antara A dan B
(ii) Antara C dan D
b. Periode susunan pegas:
(i) Antara A dan B
(ii) Antara C dan D

Pd ssunan pgas A, B, C, & D, tntukan nilai prbandingan

Jawaban Terkonfirmasi

1/kA = 1/k + 1/k
= 2/k
kA = k/2
kB = k
kC paralel = k + k = 2k
1/kC = 1/2k + 1/k
= 3/2k
kC = 2k/3
kDparalel1 = k + k + k = 3k
kDparalel2 = k + k = 2k
1/kD = 1/3k + 1/2k
= 5/6k
Kd = 6k/5
a(i) ΔxA : ΔxB = $frac{mA.g}{kA}$ : $frac{mB . g}{kB}$
= $frac{M}{ frac{k}{2} }$ : $frac{M}{k}$
= 2/k : 1/k
= 2 : 1
a(ii) ΔxC : ΔxD = $frac{mC . g}{kC}$ : $frac{mD . g}{kD}$
= $frac{M}{ frac{2k}{3} }$ : $frac{3M}{ frac{6k}{5} }$
= $frac{1}{ frac{2}{3} }$ : $frac{3}{ frac{6}{5} }$
= $frac{3}{2}$ : (3 . $frac{5}{6}$ )
= $frac{3}{2}$ : $frac{5}{2}$
= 3 : 5
b (i) TA : TB = 2π $sqrt{mA/KA}$ : 2π $sqrt{mB/kB}$
= $sqrt{ frac{M}{k/2} }$ : $sqrt{M/k}$
= √2 : √1
= √2 : 1
(ii) TC : TD = 2π $sqrt{mC/kC}$ : 2π $sqrt{mD/kD}$
= $sqrt{ frac{M}{2k/3} }$ : $sqrt{ frac{3M}{6k/5} }$
= $sqrt{3/2}$ : $sqrt{5/2}$
= 1/2√6 : 1/2√10
= √6 : √10