Permutasi-ayam-#nitipsendal#jangandicuri#klonyuriberartigrupwanyasiremboatok
Answer:
Permutations
"Ayam"
"Nitipsendal"
"jangandicuri"
"klonyuriberartigrupwa"
"nyasiremboatok"
Ayam
A = 2
Y = 1
M = 1
P = 4!
P = 4x3x2x1x2/1
P = 24
P = 2!/1
P = 24:2
P = 12
Nitipsendal
N = 2
I = 2
T = 1
P = 1
S = 1
E = 1
D = 1
A = 1
L = 1
P = 11!
P = 11x10x9x8x7x6x5x4x3x2x1x2/2
P = 39,916,800
P = 2!/2
P = 2×2
P = 4
P = 39,916,800:4
P = 9,979,200
Jangandicuri
J = 1
A = 2
N = 2
G = 1
D = 1
D = 1
I = 2
C = 1
U = 1
R = 1
P = 12!
P = 12x11x10x9x7x6x5x4x3x2x1x2/4
P = 479,001,600
P = 2!/4
P = 2x2x2x2
P = 16
P = 29,937,600
klonyuriberartigrupwan
K = 1
L = 1
O = 1
N = 2
Y = 1
U = 2
R = 2
I = 2
B = 1
E = 1
R = 3
A = 2
T = 1
G = 1
P = 1
W = 1
P = 22!
P = 22x21x20x19x18x17x16x15x14x13x12x11x10x9x8x7x6x5x4x3x2x1x2/13
P = 859,541,760
P = 2!/13
P = 13x12x11x10x9x8x7x6x5x4x3x2x1
P = 16,646,569
P = 859,541:16,646,579= 52.2055427
Nyasiremboatok
N = 1
Y = 1
A = 2
S = 1
I = 1
R = 1
E = 1
M = 1
B = 1
O = 2
T = 1
K = 1
P = 14!
P = 14x13x12x11x10x9x8x7x6x5x4x3x2x1x2/2
P = 726,485,760
P = 2!/2
P = 2×2
P = 4
P = 726,485,760:4
P = 181,621,440
Explain: Permutations are different arrangement of elements formed from N elements, taken from N elements or some elements
Kaidah pencacahan
- Ayam
Total huruf = 4
Unsur ganda = 2
4!/2!
= 24/2