Persamaan Garis Lurus yang melalui titik (-2,4) dan tegak lurus 2x – 3y = 4 adalah…

2x – 3y = 4
3y = 2x – 4
y = 2/3 x – 4/3

m = 2/3
tegak lurus, syarat :
m1 x m2 = -1
2/3 x m2 = -1
m2 = -3/2

melalui (-2,4)
y – y1 = m ( x – x1 )
y – 4 = -3/2 ( x + 2 )
y – 4 = -3/2 x – 3
y – 4 + 3/2 x + 3 = 0
3x + 2y – 8 + 6 = 0
3x + 2y – 2 = 0. A