Persamaan garis melalui titik (1,2)dan tegak lurus garis 2x+3y-5=0 adalah
Jawaban Terkonfirmasi
2x + 3y – 5 = 0
m₁ = -2/3
m₁m₂ = -1
m₂ = -1/m₁
= -1 / (-2/3) = 3/2
y – y₂ = m₂(x – x₂)
y – 2 = 3/2 (x -1)
y – 2 = 3/2 x – 3/2
2y – 4 = 3x – 3
-3x + 2y – 1 = 0
3x – 2y + 1 = 0
