Persamaan garis normal kurva y= x^2 – 3x + 6 di titik t (2,4)

M = y'
m = 2x – 3
m = 2(2) – 3
m = 4 – 3
m = 1
persamaan garis
y – y1 = m.(x – x1)
y – 4 = 1.(x – 2)
y = x – 2 + 4
y = x + 2