Persamaan garis singgung kurva f(x)=sin(2x-4) di titik berabsis 2 adalah …

Jawab

f(x)= sin(2x – 4)
absis 2 → x = 2
f(2) =sin(4-4) = sin 0 = 0
titik (x1, y1) = (2, 0)

m = f'(x) = 2 cos (2x -4)
x = 2 → m = 2 cos (4-4)
m = 2 cos 0
m = 2 (1)
m = 2

persamaan garis y – y1 = m (x – x1)
y – 0= 2(x – 2)
y = 2x – 4
2x – y = 4
2x – y – 4 = 0