Persamaan garis yang melalui titik (-2,5) dan (8,-3) adalah? tolong bantu jawab

x1,y1 = -2,5
x2,y2 = 8,-3

maka
y2 – y1 = -3 – 5 = -8
x2 – x1 = 8 -(-2) = 8+2 = 10

Jadi

Persamaan garis
(x2-x1)(y – y1) = (y2 – y1)(x-x1)
     10 (y -5)      = -8 (x + 2)
     5(y – 5)        = -4 (x+2)
       5y – 25      = -4x – 8
   4x + 5y – 25 + 8 = 0
 4x + 5y – 17 = 0

Semoga membantu… 🙂

Y-y1/y2-y1 = x-x1/x2-x1
y-5/-3-5 = x-(-2)/8-(-2)
y-5/-8 = x+2/10
10(y-5) = -8(x+2)
10y-50 = -8x +16
8x+10y-50+16 = 8x+10y-34 = 4x+5y-17