Persamaan garis yg tegak lurus garis y=2/3x+1 dan melalui titik (-2,-1)adalah

Y=2/3x+1
m=2/3
tegak lurus
m1xm2=-1
2/3xm2=-1
m2=-1/ 2/3
m2=-3/2 melalui (-2,-1)
y-y1=m(x-x1)
y-(-1)=-3/2(x-(-2)
y+1=-3/2x-3
y=-3/2x-3-1
y=-3/2x-4