persamaan kuadrat 2x pangkat 2+px+q=0 mempunyai akar x1=-3:2 dan x2=2p-q.Tentukan nilai x1+x2 dan x1 dikali x2

2x^2 + px + q = 0
a. b. c.

*x1 + x2 = -b/a
-3/2 + (2p-q) = -p/2
-3/2 + 2p – q = -p/2
—————————– x2
-3 + 4p – 2q = -p
5p – 2q = 3 ….(1)

*x1x2 = c/a
-3/2(2p-q) = q/2
-3p + 3/2q – q/2 =0
-3p + q = 0 ….(2)

*eleminasi (1) dan (2)
5p – 2q = 3
-3p + q = 0 | x2
-6p + 2q = 0
———————- +
-p. = 3
p = -3

*sub p = -3 ke (1)
5p – 2q = 3
5(-3) – 2q = 3
-2q = 3 + 15
-2q = 18
q = -9

*x1+x2 = -p/2 = -3/2
*x1x2 = q/2 = -9/2