Persentase massa karbon dalam senyawa C6H12N adalah?
Jawaban Terkonfirmasi
Ar C = 12
Ar H = 1
Ar N = 14
Mr C6H12N = 6 Ar C + 12 Ar H + Ar N
Mr C6H12N = 6(12) + 12(1) + 14
Mr C6H12N = 98
% C = (6 × Ar C / Mr C6H12N) × 100%
% C = (6 × 12 / 98) × 100%
% C = 73,5 %