Pertanyaan di Tentukan pH larutan NH CI 0,42 M (K, NH,OH = 1,8 x 10-6)! Jawab:​

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Pertanyaan di Tentukan pH larutan NH CI 0,42 M (K, NH,OH = 1,8 x 10-6)! Jawab:​

Jawaban:

pH = 4,5 – log sqrt{2}

Penjelasan:

[H+] = sqrt{frac{Kw}{Kb} . M. valensi garam } = sqrt{frac{10^{-14}}{1,8 . 10^{-6}} . 0,42 . 1 } = sqrt{2 . 10^{-9} } = 10^{-4,5}sqrt{2}

pH = 4,5 – log sqrt{2}