Pertidaksamaan nilai mutlak
[3x + 2] <= 5
Jawaban Terkonfirmasi
-5 <= 3x + 2 <= 5
-5 -2 <= 3x + 2 – 2 <= 5 – 2
-7 <= 3x <= 3
-7/3 <= 3x/3 <= 3/3
-7/3 <= x <= 1
Pertidaksamaan nilai mutlak
[3x + 2] <= 5
-5 <= 3x + 2 <= 5
-5 -2 <= 3x + 2 – 2 <= 5 – 2
-7 <= 3x <= 3
-7/3 <= 3x/3 <= 3/3
-7/3 <= x <= 1