Ph dari H²SO⁴ 0.02 M

Ph dari H²SO⁴ 0.02 M

Penjelasan:

${h}^{2} {so}^{4} = 0.02m \ {2h}^{ + } + {so}^{4 - } \ 0.02(2) = 0.04 = 4 times {10}^{ - 2} \ ph = - log( | {h}^{ + } | ) \ = - log(4 times {10}^{ - 2} ) \ = 2 - log(4)$