Please help !!! Nilai dari

Please help !!!
Nilai dari

Jawaban Terkonfirmasi

$displaystyle intlimits^pi_0sin2xcos x,dx=int2sin xcos xcdotcos x,dx\intlimits^pi_0sin2xcos x,dx=int2sin xcos^2x,dx\\text{misal :}\cos x=u\-sin x,dx=du\\intlimits^pi_0sin2xcos x,dx=2int u^2cdot(-[-sin x,dx])\intlimits^pi_0sin2xcos x,dx=-2int u^2,du\intlimits^pi_0sin2xcos x,dx=-frac{2}{3}u^3\intlimits^pi_0sin2xcos x,dx=left-frac{2}{3}cos^3xright|^pi_0\intlimits^pi_0sin2xcos x,dx=-frac{2}{3}cos^3pi-left(-frac23cos^30right)$
$displaystyle intlimits^pi_0sin2xcos x,dx=-frac{2}{3}(-1)^3+frac23(1)^3\intlimits^pi_0sin2xcos x,dx=frac{2}{3}+frac23\boxed{boxed{intlimits^pi_0sin2xcos x,dx=frac{4}{3}}}$