Pleass Kakak” tolong bantuin jawab soal diatas..Nanti ku follow(。•́︿•̀。)(ᗒᗩᗕ)​

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Pleass Kakak

Pleass Kakak” tolong bantuin jawab soal diatas..Nanti ku follow(。•́︿•̀。)(ᗒᗩᗕ)​

Jawab:

Penjelasan dengan langkah-langkah:

1) Jari ^2 10

=  π × r × r

= 3,14 × 10 × 10

= 314cm ²

2) Jari^2 21

=  π × r × r

=  22/7 × 21 × 21 = 66 × 21

= 1386 cm ^2

3) Diameter 30

luas lingkaran = Πr²

= 3,14 × (15) (15)

= 706,5 cm²

4) Diameter 14

d = 14 cm

r = d/2 = 7 cm

Sehingga luas lingkaran ialah:

L = π × r²

L = 22/7 × 49 = 154

5) L = phi × r × r

= 3,14 × 16 × 16

= 803,84 cm^2

Ini ya dek jawaban nya

Jawaban:

1. 314

2. 924

3. 706,5

4. 154

5. 803,84

Penjelasan dengan langkah-langkah:

1. Diketahui : r =10

Ditanya : L?

Jawab :

l = pi times r^{2}

l = 3.14 times 10 times 10

l = 314

2. Diketahui : r =21

Ditanya : L?

Jawab :

l = pi times r^{2}

l = 3.14 times 21 times 21

l = 22 times 2 times 21

l = 44 times 21

l = 924

3. Diketahui : d = 30

r = d×½

r = 30×½

r = 15

Ditanya : L?

Jawab :

l = pi times r^{2}

l = 3.14 times 15 times 15

l = 3.14 times 225

l = 706.5

4. Diketahui : d = 14

r = d×½

r = 14×½

r = 7

Ditanya : L?

Jawab :

l = pi times {r}^{2}

l = frac{22}{7} times 7 times 7

l = 22 times 7

l = 154

5. diketahui : r = 16

ditanya : L

jawab :

l = pi times {r}^{2}

l times 3.14 times 16 times 16

l = 3.14 times 256

l = 803.84

semoga membantu, tolong jadikan jawaban terbaik yaa soalnya ngetiknya lama hehe, terima kasih