Plis bantuiin jawab moga dapat pahala deh aminn

Plis bantuiin jawab moga dapat pahala deh aminn

Jawab:

Penjelasan dengan langkah-langkah:

y= ∫y' dx

soal

$sf m= y' = sqrt x (15x - 3)\\y' = 15 xsqrt x - 3 sqrt 3\\y'= 15 x^{frac{3}{2}} - 3 x^{frac{1}{2}}\\y = int {15 x^{frac{3}{2}} - 3 x^{frac{1}{2}}} dx\\y= 15.frac{2}{5}(x)^{frac{5}{2}} - 3(frac{2}{3}) (x)^{frac{3}{2 }} + C\\y= 6(x)^{frac{5}{2}} - 2 (x)^{frac{3}{2 }} + C\\y= 6x^2sqrt x - 2xsqrt x + C\\melalui (1,6) to x= 1, y = 6 \\6 - 2 + c =6\\C= 2\\y = 6x^2sqrt x - 2xsqrt x + 2\$