Plisss bantu aku Kaka pakai cara ya , yang bantu dapat pahala plus poin

10) m = (4 – 2) / (3 – 1)
m = 2 / 2
m = 1 (A)

11) (y – 2) / (4 – 2) = (x – 1) / (3 – 1)
(y – 2) / 2 = (x – 1) / 2
2(y – 2) = 2(x – 1)
y – 2 = x – 1
y = x – 1 + 2
y = x + 1 (D)

12) 2y + 2x = 3
2y = – 2x + 3
m = – 2/2 = – 1
sejajar m1 = m2 = – 1
y – 6 = – 1(x – 3)
y = – x + 3 + 6
y = – x + 9 ( A)

13) 4y – 3x = 5
4y = 3x + 5
m = ¾
sejajar m1 = m2 = ¾
y – 6 = ¾(x + 3)
y = ¾ x + 9/4 + 6
y = ¾ x + 33/4
4y = 3x + 33 (D)

14) 4y – 6x + 10 = 0
4y = 6x – 10
m = 6/4 = 3/2
tegak lurus
m1 . m2 = – 1
3/2 . m2 = – 1
m2 = – 1 ÷ 3/2
m2 = – ⅔
y + 3 = – ⅔ (x – 4)
y = – ⅔ x + 8/3 – 3
y = – ⅔ x + ⅓
3y = – 2x + 1 (tdk ada opsi)