Pls help asksksksksksksk

Pls help asksksksksksksk

$tan( x ) = tan( frac{1}{3} pi),0 leq x leq2 pi$

$tan(x) = tan( frac{1}{3}pi )$

$tan(x) = sqrt{3}$

$x = arctan(sqrt{3}) + kpi, k in mathbb{Z}$

$x = frac{pi}{3} + kpi$

$:$

Karena terdapat interval pada persamaan tersebut, sekarang cari irisannya dengan menggunakan notasi interval.

${x = frac{pi}{3} + kpi,k in mathbb{Z} } cap { 0 leq x le 2pi}$

${x = frac{pi}{3} , frac{4pi}{3} , frac{7pi}{3},... } cap { 0 leq x leq 2pi}$

$x = frac{pi}{3} , frac{4pi}{3}$

$x = frac{pi}{3} : text{atau} : frac{4pi}{3}$