Plss jangan asall yaa kakkkkk:”

~> ∆x(t) = Vox.dt

dt = ∆x/Vox ✓

~> ∆y(t) = Voy.dt – (g.dt²/2)

= Vo.sin 37°.∆x/Vo.cos 37° – (g.∆x²/2Vo².cos²37°)

= ∆x.tan 37° – (g.∆x².sec²37°/2Vo²)

= 8.0,753 – (9,8.64.1,5625.0,5/400)

= 6,024 – 1,225

= 4,799 m ~ 4,8 m thdp acuan permukaan tanah pda sumbu vertikal ✓✓