POH dr -log (2X10^5) brp ya?

POH = -log 2 x 10^5
= 5 – log 2
PH = 14 – (5 – log 2)
= 9 + log 2
Semoga bisa membantu

POH = -log( 2×10^5)
= -log 2 + -log10^5
= -log2 + 5
= 5 – log 2

semoga membantu