Q.{ 1 / 1 } ( + 50 )f(x)= x² + 5(x) – xf(4!!)=….​

f(x) = x² + 5(x) – x

f(4!!) = (4!!)² + 5(4!!) – 4!!

= 8² + 5(4!!) – 4!!

= 8² + 5(8) – 4!!

= 8² + 5(8) – 8

= 64 + 5(8) – 8

= 64 + 40 – 8

= 104 – 8

= 96

F(X) = X² + 5(X) – X

F(4!!) = (4!!)² + 5(4!!) – 4!!

F(4!!) = [ 4.2 ]² + 5[ 4.2 ] – [ 4.2 ]

F(4!!) = 8² + 5(8) – 8

F(4!!) = [ 8.8 ] + 40 – 8

F(4!!) = 64 + 40 – 8

F(4!!) = 104 – 8

F(4!!) = 96