Q. - Universityku

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$2dfrac{3}{4} + dfrac{2}{3} = dfrac{1}{2} + x$
Tentukan nilai x

Q.

SOAL 1

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$tt2dfrac{3}{4} + dfrac{2}{3} = dfrac{1}{2} + x$

$tt2 dfrac{3}{4} + dfrac{2}{3} - dfrac{1}{2} = x$

$tt2 dfrac{3}{4} + dfrac{4}{6} - dfrac{3}{6} = x$

$tt2dfrac{3}{4} + dfrac{1}{6} = x$

$2 dfrac{9}{12} + dfrac{2}{12} = x$

$tt : x : = 2 dfrac{11}{12}$

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2 3/4 + 2/3 = 1/2 + x

2 3/4 + 2/3

(2 × 4 + 3)/4 + 2/3

(8 + 3)/4 + 2/3

11/4 + 2/3

../12 + ../12

(12 ÷ 4 × 11)/12 + (12 ÷ 3 × 2)/12

(3 × 11)/12 + (4 × 2)/12

33/12 + 8/12

= 41/12

= 3 5/12

1/2 + 3 5/12

1/2 + 5/12

../12 + 5/12

(12 ÷ 2 + 1)/12 + 5/12

(6 × 1)/12 + 5/12

7/12 + 5/12

12/12

= 1

3 + 1

= 4

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