Q.(2/1)f(x) = 6x + 5x – 10Tentukanf(2) + f(3) = ….Huaa :-: ​

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Q.(2/1)f(x) = 6x + 5x - 10Tentukanf(2) + f(3) = ....Huaa :-: ​

Q.(2/1)f(x) = 6x + 5x – 10Tentukanf(2) + f(3) = ….Huaa :-: ​

Jawaban:

f(x) = 6x + 5x – 10

tentukan :

f(2) + f(3) =…

penyelesaian :

f(2) = 6(2) + 5(2) -10

f(2) = 12 + 10 – 10

f(2) = 22 – 10

f(2) = 12

f(3) = 6(3) + 5(3) – 10

f(3) = 18 + 15 – 10

f(3) = 33 – 10

f(3) = 23

maka :

f(2) + f(3)

12 + 23

= 35

#BelajarBareng

f(x) = 6x + 5x – 10

·

→ f(2) + f(3)

→ (6(2) + 5(2) – 10) + (6(3) + 5(3) – 10)

→ (12 + 10 – 10) + (18 + 15 – 10)

→ 12 + 23

→ 35

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