Q. 20³ - 35² × 0 = ..f(x) = x - 1 + 2x - x!f(2) = ..

Q. 20³ – 35² × 0 = ..f(x) = x – 1 + 2x – x!f(2) = ..

Nomor 1

20³ – 35² × 0

= ( 20 × 20 × 20 ) – 35² × 0

= ( 400 × 20 ) – 35² × 0

= 8.000 – 35² × 0

= 8.000 – ( 35 × 35 ) × 0

= 8.000 – 1.225 × 0

= 8.000 – ( 1.225 × 0 )

= 8.000 – 0

= 8.000

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Nomor 2

f(x) = x – 1 + 2x – x!

f(2) = 2 – 1 + 2(2) – 2!

f(2) = 2 – 1 + ( 2 × 2 ) – 2!

f(2) = 2 – 1 + 4 – ( 2 × 1 )

f(2) = 2 – 1 + 4 – 2

f(2) = 1 + 4 – 2

f(2) = 1 + 2

f(2) = 3

20³ – 35² × 0

( 20 x 20 x 20 ) – ( 35 x 35 ) x 0

( 400 x 20 ) – 1.225 x 0

8000 – 0

8000

f(x) = x – 1 + 2x – x!

f(2) = 2 – 1 + 2(2) – 2!

f(2) = 2 – 1 + 2(2) – ( 2 x 1 )

f(2) = 2 – 1 + 2(2) – 2

f(2) = 2 – 1 + ( 2 x 2 ) – 2

f(2) = 2 – 1 + 4 – 2

f(2) = 1 + 4 – 2

f(2) = 5 – 2

f(2) = 3

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