Q.

f(x) = x² + x² × 2 – 5

f(5) = 5² + 5² × 2 – 5

f(5) = 25 + 25 × 2 – 5

f(5) = 25 + 50 – 5

f(5) = 75 – 5

f(5) = 70

f(x) = x² + x² × 2 – 5

f(5) = 5² + 5² × 2 – 5

f(5) = (5 × 5) + 5² × 2 – 5

f(5) = 25 + 25 × 2 – 5

f(5) = 25 + 50 – 5

f(5) = 75 – 5

f(5) = 70