Q. [ + 50 ] - Universityku

Diketahui persamaan kuadrat x² + 4x – 12 = 0, Tentukan nilai $bf x_1$ dan $bf x_2$ dengan menggunakan rumus ABC

Q. [ + 50 ]

Jawab:
x₁ = 2,
x₂ = -6

Penjelasan dengan langkah-langkah:
Diketahui
1x² + 4x – 12 = 0
∵ ax² + bx + c = 0
∴ a = 1, b = 4, c = -12

Ditanya x₁ dan x₂

$sf x_{1, :2}=frac{-bpm sqrt{b^2-4ac}}{2a}\\x_{1, :2}=frac{-4pm sqrt{4^2-4(1)(-12)}}{2(1)}\\x_{1, :2}=frac{-4pm sqrt{16+48}}{2}\\x_{1, :2}=frac{-4}{2}pmfrac{sqrt{64}}{2}\\x_{1, :2}=-2pmfrac{8}{2}$
x₁ ₂ = -2±4
Hp = {-2+4, -2-4}
Hp = {2, -6}

[[ KLF ]]

•› Jwbn ｡.ﾟ

x² + 4x – 12 = 0

a = 1
b = 4
c = -12

$sf : x = frac{ - b pm sqrt{ {b}^{2} - 4ac} }{2a} \$

$sf : x=frac{-4±sqrt{4^{2}-4left(-12right)}}{2} \$

$sf x=frac{-4±sqrt{16-4left(-12right)}}{2} \$

$sf : x=frac{-4±sqrt{16+48}}{2} \$

$sf : x=frac{-4±sqrt{64}}{2} \$

$sf : x=frac{-4±8}{2} \$

$sf : x_1=frac{4}{2} \$

$sf : x_1 = 2$

$sf : x_2=frac{-12}{2} \$

$sf : x_2 = - 6$

HP = { -6, 2 }

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