Q. [ + 50 ]K = 6e = 9y = 2z = 10Tentukan :K × e ÷ y + z + 0 – 1
K × e ÷ y + z + 0 – 1 = 36
Pembahasan
= K × e ÷ y + z + 0 – 1
= 6 × 9 ÷ 2 + 10 + 0 – 1
= 54 ÷ 2 + 10 + 0 – 1
= 27 + 10 + 0 – 1
= 37 + 0 – 1
= 37 – 1
= 36
Jawaban:
K × e ÷ y + z + 0 – 1 = ?
= > 6 × 9) ÷ 2 + 10 + 0 – 1
= > 54 ÷ 2 + 10 + 0 – 1
= > 27 + 10 + 0 – 1
= > 37 + 0 – 1
= > 37 – 1
= > 36