Q.

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f(x) = 78x + 20x² – 10¹
f(11) = ..?
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Q.

f(x) = 78x + 20x² – 10¹

f(11) =

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f(11) = 78(11) + 20(11²) – 10

f(11) = ( 78 × 11 ) + 20(11 × 11) – 10

f(11) = 858 + 20(121) – 10

f(11) = 858 + 2.421 – 10

f(11) = 3.278 – 10

f(11) = 3.268

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PENYELESAIAN

f(x) = 78x + 20x² – 10¹

f(11) = 78(11) + 20(11)² – 10

f(11) = 858 + 20(121) – 10

f(11) = 858 + 2420 – 10

f(11) = 858 + 2410

f(11) = 3.268

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