Q.

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f(z) = ½(z) + 200 × 2^2+1

f(2) = ?

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Q.

~Answer -! ☆

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f(z) =  tt frac{1}{2}(z) + 200 ×  {{2}^{2+1}}

f(z) =  tt frac{1}{2}(2) + 200 × 2³

f(z) = 1 ÷ 200 × ( 2 × 2 × 2 )

f(z) = 1 ÷ 200 × ( 4 × 2 )

f(z) = 1 ÷ 200 × 8

f(z) = 1 ÷ 1.600

f(z) = 1.601

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Gambar Jawaban

f(z) = 1/2(z) + 200 × 2^2 + 1

f(2) = 1/2(2) + 200 × 2³

f(2) = 1 + 200 × (2 × 2 × 2)

f(2) = 1 + 200 × 8

f(2) = 1 + 1600

f(2) = 1601

Gambar Jawaban