f(z) = ½(z) + 200 × 2^2+1
f(2) = ?
Q.
~Answer -! ☆
______________
f(z) = (z) + 200 ×
f(z) = (2) + 200 × 2³
f(z) = 1 ÷ 200 × ( 2 × 2 × 2 )
f(z) = 1 ÷ 200 × ( 4 × 2 )
f(z) = 1 ÷ 200 × 8
f(z) = 1 ÷ 1.600
f(z) = 1.601 ✔
f(z) = 1/2(z) + 200 × 2^2 + 1
f(2) = 1/2(2) + 200 × 2³
f(2) = 1 + 200 × (2 × 2 × 2)
f(2) = 1 + 200 × 8
f(2) = 1 + 1600
f(2) = 1601