Q.Jikaa² – b² = 72a – b = 4maka,3a + 3b = ….​

" Aljabar "

___________

>>Penyelesaian :

a² – b² = 72

a² + ab – ab – b² = 72

a( a + b ) – b( a + b ) = 72

>>( a + b )( a – b ) = 72

________

a – b = 4

>> ( a + b )( a – b ) = 72

>> ( a + b )4 = 72

>> a + b = 72 ÷ 4

>> a + b = 18

_____________

3a + 3b

>> 3( a + b )

>> 3 × 18

>> 54

AljabaR

a – b = 4

a² – b² = 72

(a – b)(a + b) = 72

4 (a + b) = 72

a + b = 72/4

a + b = 18

3a + 3b = 18 × 3

3a + 3b = 54